SSC JE Electrical Engineering 2012 Paper

Question : 179 of 200

Marks: +1, -0

A lap wound dc generator having 250 armature conductor runs at 1200 rpm. If the generated emf is 200 V, then the operating flux of the dc generator is

0.08 wb
0.04 wb
0.06 wb
0.02 wb

Validate

Solution:

E_a={PZ}/{2πA}.ϕ.{2πN}/60

200={250×1200}/60×ϕ

ϕ={200×60}/{250×1200}=0.04\wb

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