SSC JE Electrical Engineering 2012 Paper

Question : 168 of 200

Marks: +1, -0

During the measurement of a low resistance using a potentiometer, the following readings were obtained :
Voltage drop across unknown resistance = 0.531 Volt.
Voltage drop across a 0.1 Ohm standard resistance connected in series with the unknown = 1.083 Volt.
Value of the unknown resistor is

49.03 milliohm
108.3 milliohm
20.4 milliohm
53.1 milliohm

Validate

Solution:

R/S=V_R/V_S

R=0.531/1.083×0.1

= 49.03 × 10

^{–3}

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