SSC JE Electrical Engineering 2012 Paper

Question : 152 of 200

Marks: +1, -0

A consumer is offered the following rate of tariff. He has to pay a fixed charge of ₹ 1,000 per month and a running charge of ₹ 4.50 per unit consumed. If the consumer runs a motor load of 1 KW at 0.85 power factor lagging on an average of 15 hours per day, his annual bill is

₹ 25637.50
₹ 36637.50
₹ 40985.29
₹ 32941.88

Validate

Solution:

Fixed charge = 12 × 1000 = 12000 Rs.
Running charges

= {1000× 15× 365}/1000× 4.5

= 24637.5
Annual bill = 36637.50 Rs.

Go to Question:

Prev Question

Next Question