SSC JE Electrical Engineering 2012 Paper

Question : 145 of 200

Marks: +1, -0

In an R-L series circuit R = 20 Ω, L = 0.056 H and the supply frequency is f = 50 Hz. The magnitude impedance of the circuit is

Solution:

Impedence = R + jwL
= 20 + j(2π × 50 × 0.056) = 20 + j17.59
Impedence

=√{20^2+17.59^2}

= 26.64 Ω

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