SSC JE Electrical Engineering 2012 Paper

Question : 118 of 200

Marks: +1, -0

The rms value of the alternating current given by the equation
i = 50 sin (314 t – 10°) + 30 sin (314 t – 20°)

Solution:

I = 50 sin (314t – 10º) + 30 sin (314t – 20º)

I_\rms=√{{50^2+30^2}/2}=41.23A

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