SSC JE Electrical Engineering 2012 Paper

Question : 116 of 200

Marks: +1, -0

At series resonance of an ac R-L-C circuit the impressed voltage is

Solution:

at series resonance

X_L = X_C

Z=√{R^2+(X_L-X_C)^2}

Z=R

V_S=√{(V_R)^2+(V_{X_C}-V_{X_L})^2}

V_{X_C}=V_{X_L}

V_S=V_R

So at series resonance impressed voltage

V_S

is equal to resistance drop.

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