SSC JE Electrical Engineering 2010 Paper

Question : 24 of 50

Marks: +1, -0

The making current of 3-phase breaker with rating 2000 MVA, 33 kV will be

Solution:

Breaking current

I_B=S/{√3 .V_2}

Where S = Current of 3-phase break with rating

V_2

= voltage.

={2000×10^6}/{√3 .33 ×10^3}=34.99KA

I_\making=2.55×I_B

= 2.55 × 34.99 = 89.22 KA
So the making current is 89.22 KA according to equation.

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