SSC JE Electrical Engineering 11 Oct 2023 Shift 3 Paper

Question : 189 of 200

Marks: +1, -0

Current (I) expression of a diode is given by: (where symbols have usual meaning)

\mathrm{I}=\mathrm{I}_0\left(\mathrm{e}^{\frac{\mathrm{qv}}{\mathrm{}^{\mathrm{\eta T}}}}-1\right)
\rm I=I_0\left(e^{\frac{\mathrm{v}}{\eta \mathrm{kT}}}\right)
\mathrm{I}=\mathrm{I}_0\left(\mathrm{e}^{\frac{\mathrm{qv}}{\mathrm{\eta kT}}}-1\right)
\mathrm{I}=\mathrm{I}_0\left(\mathrm{e}^{\frac{\mathrm{qv}}{\mathrm{} \mathrm{ \eta kT}}}-2\right)

Go to Question:

Prev Question

Next Question