SSC JE Electrical 16 Nov 2022 Shift 3 Paper

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Question : 109 of 200

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If If is the full load current/phase and %X_s is the percentage synchronous reactance, maximum power output of an alternator is:

P_max = $\;{\%X_{s}I_{f}\;×\;100}/{E}$
Pmax = $\;{I_{f}\;×\;100}/{EX_{s}}$
Pmax = $\;{EI_{f}\;×\;100}/{\%X_{s}}$
Pmax = $\;{\%X_{s}\;×\;100}/{EI_{f}}$

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