SSC JE Civil Engineering 30-Oct-2020 Shift 2 Paper

Question : 166 of 200

Marks: +1, -0

A three-hinged parabolic arch has a span of 30 m and the central rise is 5 m. It is subjected to a point load of 40 kN at a distance of 20 m from the right hinge. Calculate the vertical reaction component at its left support.

35.35 kN
40 kN
13.13 kN
26.67 kN

Validate

Solution:

Explanation:

Given:
L = 30 m
h = 5 m

\∑\F_\H = 0

\H_\A = \H_\B = \H

\∑\F_\V = 0

\R_\A + \R_\B = 40 \kN

---(1)

\∑\M_\B = 0

\R_\A × 30 - 40 × 20 = 0

{\R}_{{\A}}={80}/{3}=26.67 {\kN}

\R_\A = 26.67 \kN

Go to Question:

Prev Question

Next Question