SSC JE Civil Engineering 30-Oct-2020 Shift 2 Paper

Calculation:
Given, Total span = 6 m
Depth of beam = 85 mm per 1 m span
Total Depth of beam = 0.085 × 6 = 0.51 m
Width of beam = 230 mm = 0.230 m
We know, Unit weight of RCC structure = 25 KN/ ${\mathrm{m}}^3$
Volume of the section = L × B × H
Volume of the section = 6 × 0.230 × 0.51
Volume of the section = 0.7038 ${\mathrm{m}}^3$
Dead load of the beam = Unit weight × Volume of the section
= 25 × 0.7038
= 17.595 KN
Factored dead load of the beam = 1.5 × 17.595 = 26.39 KN