SSC JE Civil Engineering 30-Oct-2020 Shift 2 Paper

Given equation is :
596 - 125 ÷ 19 + 65 × 2 = 598
(i) 596 - 125 ÷ 19 + 65 × 2 = 598
Interchanging 9 and 6 on the left hand side of the equation and applying BODMAS rule,
569 - 125 ÷ 16 + 95 × 2 = 598
569 - 7.8125 + 95 × 2 = 598
569 - 7.8125 + 190 = 598
759 - 7.8125 = 598
751.1875
LHS ≠ RHS.
(ii) 596 - 125 ÷ 19 + 65 × 2 = 598
Interchanging 1 and 9 on the left hand side of the equation and applying BODMAS rule,
516 - 125 ÷ 91 + 65 × 2 = 598
516 - 1.3736 + 65 × 2 = 598
516 - 1.3736 + 130 = 598
646 - 1.3736 = 598
644.6264 ≠ 598
LHS ≠ RHS.
(iii) 596 - 125 ÷ 19 + 65 × 2 = 598
Interchanging 5 and 6 on the left hand side of the equation and applying BODMAS rule,
695 - 126 ÷ 19 + 56 × 2 = 598
695 - 6.6316 + 56 × 2 = 598
695 - 6.6316 + 112 = 598
807 - 6.6316 = 598
800.3684 ≠ 598
LHS ≠ RHS.
(iv) 596 - 125 ÷ 19 + 65 × 2 = 598
Interchanging 2 and 5 on the left hand side of the equation and applying BODMAS rule,
296 - 152 ÷ 19 + 62 × 5 = 598
296 - 8 + 62 × 5 = 598
296 - 8 + 310 = 598
606 - 8 = 598
598 = 598
LHS = RHS
Hence, the correct answer is "2 and 5".