SSC JE Civil Engineering 30-Oct-2020 Shift 2 Paper

Question : 123 of 200

Marks: +1, -0

g1 = + 1.2%

and

\g2

= + 0.8% and rate of change of grade = 0.1% per 20 m chain, then the length of the vertical curve is

10 m
15 m
30 m
80 m

Validate

Solution:

Concept:
Total Grade = Grade 1 – Grade 2
Length of curve

= (\text "Total grade"/\text "Rate of change of grade per chain length") × \text "Length of chain"

Calculation:
An upgrade of + 1.2% joins another upgrade of + 0.8%.
Grade = + 1.2 – (+ 0.8) = 0.4 % (Upward)
Change of grade is 0.1% per 20 m chain.

\L = (0.4/0.1) × 20

= 80 m

Go to Question:

Prev Question

Next Question