SSC JE Civil Engineering 30-Oct-2020 Shift 2 Paper

Question : 118 of 200

Marks: +1, -0

The overall efficiency of a centrifugal pump when head is 25 m,

\discharge = 0.04 \m^3\/\s

and output power p = 16 kW (take

\g = 10 \m^3\/\s^2

and ρ = 1000) is

65%
55%
52.5%
62.5%

Validate

Solution:

Explanation:
Overall Efficiency (η): It is defined as a ratio of the power output of the pump to the power input to the pump.
The overall efficiency of the pump will be given as,

\η={\text " water power "}/{\text " shaft power"}={\ω\Q\H}/{\P}

{\P}={\ω\Q\H}/\η

Calculation:

\η={ \ρ\g\Q\H}/{\P}

={1000 ×10 ×0.04 ×25}/{16000}

=0.625

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