SSC JE Civil Engineering 30-Oct-2020 Shift 2 Paper

Question : 116 of 200

Marks: +1, -0

A simply supported beam of span 6 m carries an ultimate UDL of 25 kN/m. The plastic moment capacity of the same is

Solution:

Concept:
Plastic moment capacity for the simply supported beam with UDL;

\M_\p= {\w\l^2}/8

Calculation:
Given;

\w = 25 \KN\/\m

\l= 6 \m

From above equation:

\M_\p={25×6^2}/88 = 112.5

$\M_\p = 112.5 \KN - \m$

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