SSC JE Civil Engineering 30-Oct-2020 Shift 1 Paper

First number $={\left(\mathrm{Second}\mathrm{number}+1\right)}^4-14$
Second number = 5
First number $={\left(\mathrm{Second}\mathrm{number}+1\right)}^4-14$ $={\left(5+1\right)}^4-14$ $=6^4-14$ $=1296-14$ $=1282$
Similarly,
Third number $={\left(\mathrm{Fourth}\mathrm{Number}+1\right)}^4-14$
Fourth number $=6$
Third number $={\left(\mathrm{Fourth}\mathrm{number}+1\right)}^4-14$ $={\left(6+1\right)}^4-14$ $=7^4-14$ $=2401-14$ $=2387$
So, 1282 : 5 :: 2387 : 6
Hence, the correct answer is "2387".