SSC JE Civil Engineering 30-Oct-2020 Shift 1 Paper

The logic follows here is :
Given series : 7, 11, 35, 67, 203, ?
7 (1st number)
$\left(7-2\right)\times 2+{\left(1\right)}^3=11$ (2nd number)
$\left(11-2\right)\times 3+{\left(2\right)}^3=35$ (3rd number)
$\left(35-2\right)\times 2+{\left(1\right)}^3=67$ (4th number)
$\left(67-2\right)\times 3+{\left(2\right)}^3=203$ (5th number)
$\left(203-2\right)\times 2+{\left(1\right)}^3=403$ (final number)
Hence, the correct answer is "403".