SSC JE Civil Engineering 30-Oct-2020 Shift 1 Paper

Question : 170 of 200

Marks: +1, -0

A UDL of 10 kN / m of length 5 m is moving from left to right support on a simply supported beam of span 10 m. The maximum bending moment at 4 m from the left support is:

70 kN-m
90 kN-m
50 kN-m
30 kN-m

Validate

Solution:

Maximum bending moment at C:
Maximum bending moment at C will occur when average loading just to the left of C is equal to average loading just to right of C.

{x}/{5-x}={4}/{6}

So,

x=2 {\m}

Maximum bending moment = Area of ILD below loading (rectangle + triangle) × w
= [(1.2 × 5) + 0.5 × (5 × 1.2)] × 10 = 90 KN-m

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