SSC JE Civil Engineering 30-Oct-2020 Shift 1 Paper

Question : 167 of 200

Marks: +1, -0

The sleeper density of a broad gauge track is (M + 7) in metric units, where M is length of rail in metres. The number of sleepers for 1.024 km length of track is:

1700
1500
1600
1900

Validate

Solution:

On Indian railways standard length of BG rail = 13 m
So, total no. of rail required in 1.024 km or 1024 m

= 1024/13

= 78.78 = 80 (in round figure)
Sleeper density = M + 7
M = length of rail
So, sleeper density = 13 + 7 = 20
No. of sleepers = 20 × 80 = 1600

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