SSC JE Civil Engineering 30-Oct-2020 Shift 1 Paper

The FEM’s when a beam is subjected to point load and clear loading such as uDL is given below: Calculation:
a = 2m
b = 3m
L = a + b = 5m
P = 50 kN
$\mathrm{M}\underset{\mathrm{AB}}{\overset{\mathrm{F}}{}}=-\frac{{\mathrm{Pb}}^2\mathrm{a}}{{\mathrm{L}}^2}$ $=-\frac{50\times {\left(3\right)}^2\times 2}{{\left(5\right)}^2}$ $=-36\mathrm{kNm}(\uparrow )$
(-ve sign means that $\mathrm{M}\underset{\mathrm{AB}}{\overset{\mathrm{F}}{}}$ is in Anticlockwises)
$\mathrm{M}\underset{\mathrm{AB}}{\overset{\mathrm{F}}{}}=+\frac{{\mathrm{Pa}}^2\mathrm{b}}{{\mathrm{L}}^2}$ $=\frac{50\times {\left(2\right)}^2\times 3}{{\left(5\right)}^2}$ $=+24\mathrm{kNm}(\uparrow )$