SSC JE Civil Engineering 29-Oct-2020 Shift 1 Paper

Code = Sum of positional values + 5
For ROUGH:
Sum of positional values:
R + O + U + G + H = 18 + 15 + 21 + 7 + 8 = 69
Code = 69 + 5 = 74.
For SPACE:
Sum of positional values:
S + P + A + C + E = 19 + 16 + 1 + 3 + 5= 44
Code = 44 + 5 = 49.
Similarly,
For CLERK:
Sum of positional values:
C + L + E + R + K = 3 + 12 + 5 + 18 + 11 = 49
Code = 49 + 5 = 54
So, the code for CLERK is 54.
Hence, the correct answer is "54".