SSC JE Civil Engineering 29-Oct-2020 Shift 1 Paper

The pattern follows here is :
Positional values of consonants are getting doubled.
Vowels are having place values as per they appear in vowel sequence.
$\begin{array}{cccccc}\mathrm{L}& \mathrm{A}& \mathrm{Y}& \mathrm{M}& \mathrm{A}& \mathrm{N}\\ \left(12\right)& \left(1\right)& \left(25\right)& \left(13\right)& \left(1\right)& \left(14\right)\\ \downarrow & \downarrow & \downarrow & \downarrow & \downarrow & \downarrow \\ 24& 1& 50& 26& 1& 28\end{array}$

$\begin{array}{ccccccc}\mathrm{A}& \mathrm{L}& \mathrm{G}& \mathrm{E}& \mathrm{B}& \mathrm{R}& \mathrm{A}\\ \left(1\right)& \left(12\right)& \left(7\right)& \left(5\right)& \left(2\right)& \left(18\right)& \left(1\right)\\ \downarrow & \downarrow & \downarrow & \downarrow & \downarrow & \downarrow & \downarrow \\ 1& 24& 14& 2& 4& 36& 1\end{array}$

Similarly,
$\begin{array}{cccccccc}\mathrm{F}& \mathrm{U}& \mathrm{N}& \mathrm{C}& \mathrm{T}& \mathrm{I}& \mathrm{O}& \mathrm{N}\\ \left(6\right)& \left(21\right)& \left(14\right)& \left(3\right)& \left(20\right)& \left(9\right)& \left(15\right)& \left(14\right)\\ \downarrow & \downarrow & \downarrow & \downarrow & \downarrow & \downarrow & \downarrow & \downarrow \\ 12& 5& 28& 6& 40& 3& 4& 28\end{array}$
Hence, the correct answer is "125286403428".