SSC JE Civil Engineering 29-Oct-2020 Shift 1 Paper

Below Diagram shows the shortest distance between the starting point and the ending point denoted by point P and R respectively. Now, Triangle "PRQ" is a right-angled triangle, so using Pythagoras Theorem:
PQ = PC + CQ
PQ = 70 + 70
PQ = 140
RQ = CS = 35
${\mathrm{PR}}^2={\mathrm{PQ}}^2+{\mathrm{RQ}}^2$
${\mathrm{PR}}^2={\left(140\right)}^2+{\left(35\right)}^2$
${\mathrm{PR}}^2=19600+1225$
${\mathrm{PR}}^2=20825$
$\mathrm{PR}=\sqrt{20825}$
PR is approximately equal to 144 m.
Hence, the correct answer is "144 m".