SSC JE Civil Engineering 29-Oct-2020 Shift 1 Paper

The logic follows here is :
Square of 3rd term × 3 = 1st term,
Square of 3rd term × 2 = 2nd term,
(243, 162, 9) → $\left(9^2\times 3=243\right),$ $\left(9^2\times 2=162\right)$
1). (100, 50, 5) → $\left(5^2\times 3\ne 100\right),$ $\left(5^2\times 2=50\right)$
2). (278, 78, 8) → $\left(8^2\times 3\ne 278\right)$ , $\left(8^2\times 2\ne 78\right)$
3). (48, 32, 4) → $\left(4^2\times 3=48\right),$ $\left(4^2\times 2=32\right)$
4). (225, 25, 5) → $\left(5^2\times 3\ne 225\right),$ $\left(5^2\times 2\ne 25\right)$
Hence, the correct answer is "(48, 32, 4)".