SSC JE Civil Engineering 29-Oct-2020 Shift 1 Paper

Question : 159 of 200

Marks: +1, -0

Estimate the quantity of brick masonry required for construction of a room of 4 m × 3 m internal dimensions. Thickness of wall should be 250 mm. Two windows of 2 m × 1.5 m and one door of 1.5 m × 2.2 m is to be provided to the room. Height between top of plinth beam and bottom of slab beam should be 4 m.

13.918 $\m^3$
9.420 $\m^3$
15.935 $\m^3$
12.675 $\m^3$

Validate

Solution:

This is solved by using centre line method.

Total centre line length

= (4 + .25) × 2 + (3 + .25) × 2

= 15 \m

Height of wall = 4 m
Thickness of wall = 0.25 m.
Window area

= 2 × 2 × 1.5 = 6 \m^2

Door area

= 1.5 × 2.2 = 3.3 \m^2

Total opening area = where no need of brick work

= 6 + 3.3 = 9.3 \m^2

Net effective area, where brickwork is to be done is given as:
= (Centre line length) × Height – opening area

= 15 × 4 -9.3 = 50.7 \m^2

Qty of brick work = (effective area) × Thickness of wall

= 50.7 × 0.25

= 12.675 \m^2

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