SSC JE Civil Engineering 29-Oct-2020 Shift 1 Paper

Joint D:
Member DC and DE are non-collinear and No external load an joint D.
So
${\mathrm{F}}_{\mathrm{DE}}={\mathrm{F}}_{\mathrm{DC}}=0$ Rule 2
Joint E : $\sum {\mathit{F}}_{\mathit{y}}=0$
$\Rightarrow {\mathit{F}}_{\mathit{E}\mathit{F}}=0$
$\sum {\mathit{F}}_{\mathit{x}}=0$
Joint C:
${\mathit{F}}_{\mathit{E}2}=+5\mathit{k}\mathit{N}$ (Tensile)${\mathit{F}}_{\mathit{C}\mathit{I}}=0$ Rule (2)
${\mathit{F}}_{\mathit{C}\mathit{B}}=0$ Rule (2)
Zero force members
Area DE, DC, EF, CI, CB
Tube are shown in above diagram.