SSC JE Civil Engineering 29-Oct-2020 Shift 1 Paper

Question : 119 of 200

Marks: +1, -0

A simply supported beam of span 'L' is carrying uniformly distributed load 'w' on the entire span. If uniformly distributed load is replaced by a concentrated load 'W' at centre such that it produces same deflection at centre. Keeping all other parameters same, ratio of 'W' to 'w' will be:

${5L}/{8}$
${5L}/{48EI}$
${L}/{8}$
${8L}/{5}$

Validate

Solution:

Concept:
The standard deflection and slope formulas of simply supported beam under various loading conditions are given below:

Calculation:
Given that:
Deflection under UDL at centre = Deflection under point load at centre.

{5}/{{384}}{{w{L^4}}}/{{EI}} = {{W{L^3}}}/{{48\;EI}}

⇒ {W}/{w} = {{5L}}/{8}

Go to Question:

Prev Question

Next Question