SSC JE Civil Engineering 25-Sep-2019 Shift 1 Solved Paper

Question : 148 of 200

Marks: +1, -0

Estimate the distance to the centre of pressure below the free surface, for a vertical triangular plane area submerged in water (as in the given figure) with one side on the free surface, vertex downward and altitude h.

$h/3$
${2h}/3$
${3h}/4$
$h/2$

Validate

Solution:

∵C_G = h↖{-} =h/ 3

Center of pressure h* =

{I_hSm^2θ}/{Ah↖{-} } +h↖{-}

∴

I_h = {bh^3 } /36∵ Q = 90°

h*= [{bh^3× 2 ×3 }/{36×bh×h}+h/3]

[h/6+h/3]=[{h+2h}/6]=[{3h}/6]

[h*=h/2]

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