SSC JE Civil Engineering 25-Sep-2019 Shift 1 Solved Paper

Question : 135 of 200

Marks: +1, -0

For a material having modulus of elasticity E and modulus of rigidity N, it is seen that E = 2 N. The bulk modulus K of the material is:

Solution:

As we known that

E={3K}/(1-2µ)={2G}/(1+µ)\;\;\;\;(∵N = G)

Since E = 2N

2N={2N}/{1+µ} \;\;\;\;∵µ=0

E={3K}/(1-0)

Hence,

K=E/3

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