SSC JE Civil Engineering 25-Sep-2019 Shift 1 Solved Paper

Question : 103 of 200

Marks: +1, -0

The radius of a horizontal circular curve is 100 m.
The design speed is 50 km/h and the design coefficient of lateral friction is 0.15. Determine the rate of superelevation to be provided, if full lateral friction is assumed to develop.

1 in 21.2
1 in 10.5
1 in 26.4
1 in 17

Validate

Solution:

As given that,
R = 100m, V = 50km/h, f = 0.15
As we known that,

(f + e) =V^2/{RG}=V^2/{127R}

Where, f = coefficient of lateral friction
e = super elevation

f + e = (50)^2/{127×100}

e = 0.197 - 0.15

e = 0.047 = 1 \in[1/0.047]=1 \in 21.27

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