SSC JE Civil Engineering 23-Mar-2021 Shift 2 Paper

Question : 160 of 200

Marks: +1, -0

What will be ruling minimum radius for horizontal curve of NH (National Highway) in plain terrain? (Assume ruling design speed = 127 km/h, minimum design speed = 80 km/h, rate of super elevation e = 0.05 and coefficient of friction = 0.05)

400 m
800 m
1270 m
1300 m

Validate

Solution:

V = 127 km/h
e = 0.05
f = 0.05
So, The ruling minimum radius for the horizontal curve

{e}+{\f}={{\V}^{2}}/{127 {\R}_{{\ruling }}}

0.05+0.05={(127)^{2}}/{127 {\R}_{{\ruling }}}

{\R}_{{\ruling }}={1 2 7 0} {\m}

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