SSC JE Civil Engineering 23-Mar-2021 Shift 2 Paper

Question : 111 of 200

Marks: +1, -0

A machine purchased at a cost of Rs.10,000 has a useful life of two years. The amount which is to be set aside annually as sinking fund at the rate of 10% compound interest will be

Rs. $1000/ 0.10$
Rs. $1000/ 0.31$
Rs. $1000/ 0.21$
Rs. $1000/ 1.10$

Validate

Solution:

Given: R = 10%, n = 2 years, S = 10000
Annual installment of sinking fund,

\S_{\c}={\SR}/{(1+\R)^{\n}-1}

{\S}_{{\c}}={10000 ×0.1}/{(1+0.1)^{2}-1}=1000/0.21

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