Midhun smashes 96 runs against Zimbabwe in 18 balls. If he scored his runs by hitting fours and sixes only, then find the maximum percentage of runs he scored by hitting fours..
Midhun smashes 96 runs against Zimbabwe in 18 balls. If he scored his runs by hitting fours and sixes only. then to score 96 runs in 18 balls by 4s and 6s only. No. of 4s will be equal to 6 and No. of 6s will be equal to 12. Total smashed runs by 4s = 4 × 6 = 24 Total smashed runs by 6s = 6 × 12 = 72 Total Smashed run is 72 + 24 = 96 in 18 balls. Maximum percentage of runs scored by hitting 4s = ( Total runs smashed by 4s ÷ Total runs ) × 100 Maximum percentage of runs scored by hitting 4s = ( 24 ÷ 96 ) × 100 Maximum percentage of runs scored by hitting 4s = 25% Hence, the correct answer is "Option (2)".