SSC JE Civil Engineering 23-Mar-2021 Shift 1 Paper

No of Joints, j = 3
No of support reactions, r = 5 ( 3 at support A, 1 at each support B and C)
No of axially rigid members, m = 0 (assumed as not given in Question)
${\mathrm{D}}_{\mathrm{k}}\mathit{­}=3\mathrm{j}-\mathrm{r}-\mathrm{m}$
${\mathrm{D}}_{\mathrm{k}}=3\times 3-5-0$
$\therefore {\mathrm{D}}_{\mathrm{k}}=4$