SSC JE Civil Engineering 23-Mar-2021 Shift 1 Paper

Question : 121 of 200

Marks: +1, -0

The amount of cement required for 100

\m^2

area, of damp proof course with 2.5 cm thickness, in with proportion of 1∶ 2 ∶4 (cement ∶ sand ∶ aggregate) will be:

1.10 $\m^3$
0.55 $\m^3$
0.25 $\m^3$
2.5 $\m^3$

Validate

Solution:

Concept:
Wet quantity of concrete = Area × thickness
Dry Volume of concrete = 1.54 × Wet volume of concrete
No. of cement bags = Cement quantity / 0.035
Calculation:
Area = 100 sq.m
Thickness = 2.5 cm
Concrete grade = 1:2:4
Wet quantity of concrete = 100 × 0.025 = 2.5

\m^3

So, dry quantity of concrete required = 1.54 × 2.5 = 3.85

\m^3

Quantity of cement required = 3.85 / (1+2+4) = 0.55

\m ^3

Important Point:
Ratios are of cement : sand : coarse aggregate

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