SSC JE Civil Engineering 23-Mar-2021 Shift 1 Paper

Question : 116 of 200

Marks: +1, -0

A village has a population of 200 with an average rate of water demand of 100 litres per capita per day. A rapid sand filter having an average filtration rate of 100 liter/hour/

\m^2

is to be designed for water treatment. The area of rapid sand filter required is:
(Take the ratio of maximum demand to average demand as 1.5)

14.50 $\m^2$
8.00 $\m^2$
12.50 $\m^2$
10.00 $\m^2$

Validate

Solution:

Explanation:
Given Data:
Village population = 200
The average rate of water demand = 100 litres per capita per day
average filtration rate = 100 liter/hour/

\m^2

= 100 x 24 liter/day/

\m^2

Ratio of maximum demand to average demand = 1.5
Design dicharge = 1.5 × Village population x average rate of water demand= 1.5 x 200 × 100 = 30000 liter/day/ $\m^2$
Area of rapid sand filter

={{ \Design \discharge }}/{{ \Average \filtration \rate }}

Area of rapid sand filter

={30000}/{100× 24}

Area of rapid sand filter $=12.5 {\m}^{2}$

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