The general expression for the B.M. of a beam of length\l is M ={w\l}/2x-{wx^2}/2 , the beam carries

Correct Answer is : a uniformly distributed load ‘w’ per unit length

a uniformly distributed load ‘w’ per unit length

a load varying linearly from zero at one endto w at the other end

SSC JE Civil Engineering 2018 Set 5 Solved Paper

Question : 190 of 200

Marks: +1, -0

The general expression for the B.M. of a beam of length

\l

M ={w\l}/2x-{wx^2}/2 ,

the beam carries

Solution:

R_A + R_B = W\l

ΣH_A=0

R_B× \l+ W× \l× 1/ 2 =0

R_B={W\l}/2

ΣHx = 0

{W\l}/2.x={wx^2}/2 =Hx

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