SSC JE Civil Engineering 2018 Set 5 Solved Paper

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Question : 152 of 200

Marks: +1, -0

If

R_1 = 1.1

and

R_2 = 1.2

, then what is value of

L_r

(in psf)?

26.1
26.2
26.3
26.4

Solution:

L_r = (L_1 . L_2)

L_r(\psf) = 20(1.1 × 1.2) = 26.4 \psf

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