SSC JE Civil Engineering 2018 Set 5 Solved Paper

Question : 148 of 200

Marks: +1, -0

Calculate the capacity (vehicle per hour) of the road when reaction time of the driver is 2 seconds. The design speed is 80 kmph and average length of the vehicle is 6 m. Take coefficient of friction as 0.35.

Validate

Solution:

SSO =vt+V^2/ {254\f}

0.278× 80 ×2+80^2/{ 254× 0.35}

= 1.16.471 m
Length of vehicle = 6 m
S = 116.471 + 6 m = 1.22.47

k=1000/5=1000/122.47=8.165

q = kxv
q = 8.165 × 80
q = 653.22 veh/hour
q = 653 veh / hour

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