SSC JE Civil Engineering 2018 Set 4 Solved Paper

Question : 34 of 200

Marks: +1, -0

If 11 @ 7 = 2, 18 @ 0 = 9 and 22 @ 20 = 1, then find the value of 16 @ 10 = ?

Solution:

11@7 = 2 ⇒

[{11-7}/2=2],

18@0 = 9 ⇒

[{18-0}/2=9],

22@20 = 1 ⇒

[{22-20}/2=1],

16@10 =

{16 -10} /2=3

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