SSC JE Civil Engineering 2018 Set 3 Solved Paper

Question : 143 of 200

Marks: +1, -0

Calculate the specific energy (m-kg/kg) of the flow if the velocity of flow is 2.22 m/s and depth of flow is 1 m.

Solution:

y = 1 m
v = 2.22 m/sec
specific energy

E=y+v^2/{2g}

E=1+2.22^2/{2×9.81}

[E =1.25 m]

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