SSC JE Civil Engineering 2018 Set 3 Solved Paper

Question : 136 of 200

Marks: +1, -0

The diameter of droplet is 0.075 mm. What is the intensity of the pressure (N/sq.cm) developed in the droplet by surface tension of 0.000075 N/mm?

Solution:

Δp={2σ}/r

r = radius of bubble =

0.075/2= 0.0375

mm
s = surface tension in droplet = 0.000075 N/mm
Intensity of pressure =

{2 ×0.000075}/0.0375

= 4 × 10^{–3} \N\/\mm^2.

= 0.4 \N\/\cm^2

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