SSC JE Civil Engineering 2018 Set 3 Solved Paper

Question : 120 of 200

Marks: +1, -0

Calculate the weight (kg) per meter length of 25 mm diameter steel bar place at a spacing of 250 mm center by center for 1 meter.

Solution:

Volume of steel used

=({\length \of \bar}/{\spacing})×

Area of one bar × length of bar

=(1000/250)×π/4×(0.025)^2×1

= 1.9635 × 10^{–3}

.
Take density of steel = 7850 kg/m

^{3}

\mass/\volume

Mass of steel (kg)

= 7850 × 1.9635 × 10^{–3}

.
= 15.413 kg

Go to Question:

Prev Question

Next Question