SSC JE Civil Engineering 2018 Set 1 Solved Paper

Question : 34 of 200

Marks: +1, -0

If 17

\$

22 = 4 and 56

\$

13 = 7, then find the value of 71

\$

25 = ?

Solution:

\$

22 = 4
⇒ (1 + 7) – (2 + 2) = 4
similarly 56

\$

13 = 7
⇒ (5 + 6) – (1 + 3) = 7
similarly 71

\$

25 = (7 + 1) – (2 + 5) = 1

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