SSC JE Civil Engineering 2018 Set 1 Solved Paper

Question : 196 of 200

Marks: +1, -0

Two bars of different materials are of the same size and are subjected to same tensile forces. If the bars have unit elongations in the ratio of 4 : 7, then the ratio of modulius of elasticity of the two materials is
A. 4:7
B. 4:10
C. 16:49

A only
B only
C only
None of these

Validate

Solution:

∆={PL}/ {AE}

P_1=P_2

A_1=A_2

L_1=L_2

{∆_1}/{∆_2}=4/7

{{∆_1} ={P_1L_1}/{AE}} /{{∆_2}={P_2L_2}/{A_2E_2}}

{∆_1}/{∆_2}=E_1/E_2

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