SSC JE Civil Engineering 2018 Set 1 Solved Paper

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Question : 136 of 200

Marks: +1, -0

Pressure of 200 kPa is equivalent to the head of z metre of liquid having relative density 1.59. The value of z (m) is______.

11.6
11.82
12.82
13.14

Solution:

P = ρgh

200 × 10^3 Pa = (1000 × 1.59) × 9.81 × Z

Z = 12.82 m.

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