SSC JE Civil Engineering 2018 Set 1 Solved Paper

Question : 127 of 200

Marks: +1, -0

Calculate the combined correction for curvature and refraction (in m) for a distance of 2 km.

Solution:

Combined connection

C_c = -0.06728 d^2

d = 2km = Distance

C_c =-0.067258 × 2 × 2

[C_c= 0.296 \m]

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