SSC JE Civil Engineering 2017 Set 1 Solved Paper

Question : 170 of 200

Marks: +1, -0

If a rolled steel flat designated as 55 I.S.F. 12 mm is used as lacing, then minimum radius of gyration will be .......... .

Solution:

Minimum radius of gyration,

r_{\min}=t/√12=12/√12=3.45\mm

Go to Question:

Prev Question

Next Question