SSC JE Civil Engineering 2017 Set 1 Solved Paper

Question : 136 of 200

Marks: +1, -0

If a close coiled helical spring absorbs 30 Nmm of energy while extending by 5mm, its stiffness will be ........ .

Solution:

U=1/2kx^2

⇒k={2×30}/5^2

= 2.4N / mm

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