SSC JE Civil Engineering 2017 Set 1 Solved Paper

${\mathit{\tau }}_{\max }=\frac{6\mathit{F}\left({\left(\frac{\mathit{d}}{2}\right)}^2-{\mathit{y}}^2\right)}{\mathit{b}{\mathit{d}}^3}$
This shows that there is a parabolic distribution of shear stress with y.
The maximum value of shear stress would obviously be at the location y = 0.
Therefore maximum bending stress will be occur at middle of the longer side.